$A$ horizontal force $F = mg/3$ is applied on the upper surface of a uniform cube of mass $‘m’$ and side $‘a’$ which is resting on a rough horizontal surface having $\mu_S = 1/2$. The distance between lines of action of $‘mg’$ and normal reaction $‘N’$ is :
$a/2$
$a/3$
$a/4$
None
$A$ rod of weight $w$ is supported by two parallel knife edges $A$ and $B$ and is in equilibrium in a horizontal position. The knives are at a distance $d$ from each other. The centre of mass of the rod is at a distance $x$ from $A$.
Two uniform rods of equal length but different masses are rigidly joined to form an $L$ -shaped body, which is then pivoted as shown. If in equilibrium the body is in the shown configuration, ratio $M/m$ will be:
A uniform meter scale is supported from its $20\ cm$ mark. A body suspended from $10\ cm$ mark keeps the scale horizontal. However, the scale gets unbalanced if the body is completely immersed in water. To regain the balance the body is shifted to the $8\ cm$ mark. Therefore, the specific gravity of the material of the body is
A uniform rod of length $1\, m$ and mass $4\, kg$ is supported on two knife-edges placed $10 \,cm$ from each end. A $60\, N$ weight is suspended at $30\, cm$ from one end. The reactions at the knife edges is
$A$ right triangular plate $ABC$ of mass $m$ is free to rotate in the vertical plane about a fixed horizontal axis through $A$. It is supported by a string such that the side $AB$ is horizontal. The reaction at the support $A$ is: