6.System of Particles and Rotational Motion
medium

The resultant of the system in the figure is a force of $8N$ parallel to the given force through $R$. The value of $PR$ equals to 

A

${1/4}\,\,RQ$

B

${3/8}\,\,RQ$

C

${3/5}\,\,RQ$

D

${2/5}\,\,RQ$

Solution

By taking moment of forces about point R,     $5 \times PR – 3 \times RQ = 0$

$⇒$ $PR = \frac{3}{5}RQ$.

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.