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6-2.Equilibrium-II (Ionic Equilibrium)
medium
$K_{sp}$ for $AgBr$ at $25\,^oC$ is $4.9 × 10^{-13}$. How much $AgBr$ will dissolved in $20\ litres$ of its saturated solution if molecular weight of $AgBr =$ $188$
A
$7 × 10^{-7} × 188\ gm$
B
$14 × 10^{-6} × 188\ gm$
C
$14 × 10^{-7} × 188\ gm$
D
$7 × 10^{-7} × (188)^{-1}\ gm$
Solution
$\mathrm{K}_{\mathrm{sp}}=\mathrm{S}^{2}$
$49 \times 10^{-14}=\mathrm{S}^{2}$
$\mathrm{S}=7 \times 10^{-7}\, \mathrm{mol} / \mathrm{l}$
$\because 7 \times 10^{-7} \times 20 \times 188$
$=14 \times 188 \times 10^{-6}$
Standard 11
Chemistry
