If concentration of lead iodide in its saturated solution at {25,^o}C be 2 × {10^{ - 3}} moles per

English

Gujarati

Hindi

6-2.Equilibrium-II (Ionic Equilibrium)

medium

If the concentration of lead iodide in its saturated solution at ${25\,^o}C$ be $2 \times {10^{ - 3}}$ moles per litre, then its solubility product is

A

$4 \times {10^{ - 6}}$

B

$8 \times {10^{ - 12}}$

C

$6 \times {10^{ - 9}}$

D

$32 \times {10^{ - 9}}$

Solution

(d) $\mathop {Pb{I_2}}\limits_{{K_{sp}}} ⇌ \mathop {P{b^{ + 2 }}}\limits_{S\,\,\,\,\,\,} + \mathop {2{I^ – }}\limits_{2S\,\,\,} $

${K_{sp}} = 4{S^3} = 4 \times {[2 \times {10^{ – 3}}]^3}$$ = 32 \times {10^{ – 9}}$.

Standard 11

Chemistry

Share

Similar Questions

Which one of the following is most soluble

hard

(AIPMT-1994)

${K_{sp}}$ for $Cr{(OH)_3}$ is $2.7 \times {10^{ – 31}}$. What is its solubility in moles / litre.

medium

The solubility of $CuBr$ is $2 \times {10^{ – 4}}\,mol/l$ at $25\,^oC$. The ${K_{sp}}$ value for $CuBr$ is

medium

(AIIMS-2002)

The $K _{ sp }$ for bismuth sulphide $\left( Bi _{2} S _{3}\right)$ is $1.08 \times 10^{-73}$. The solubility of $Bi _{2} S _{3}$ in $mol \,L ^{-1}$ at $298 \,K$ is ……

medium

(JEE MAIN-2022)

In qualitative analysis, the metals of group $I$ can be separated from other ions by precipitating them as chloride salts. A solution initially contains $Ag^+$ and $Pb^{2+}$ at a concentration of $0.10 \,M.$ Aqueous $HCl$ is added to this solution until the $Cl^-$ concentration is $0.10\, M.$What will the concentrations of $Ag^+$ and $Pb^{2+}$ be at equilibrium ? ($K_{sp}$ for $AgCl = 1.8 \times 10^{-10},$$ K_{sp}$ for $PbCl_2 = 1.7 \times 10^{-5}$)

hard

(AIPMT-2011)