Mathematical Reasoning
normal

$\left( { \sim \left( {p \vee q} \right)} \right) \vee \left( { \sim p \wedge q} \right)$ is logically equivalent to 

A

$ \sim p$

B

$p$

C

$q$

D

$ \sim q$

Solution

$ \sim (p \vee q) \vee ( \sim p \wedge q) \equiv ( \sim \;p \vee {\rm{ }} \sim \;q) \vee ( \sim \;p \wedge q)$

$ \sim p \wedge ( \sim q \vee q) \equiv {\rm{ }} \sim p \wedge t \equiv  \sim p$

Standard 11
Mathematics

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