$\left( { \sim \left( {p \vee q} \right)} \right) \vee \left( { \sim p \wedge q} \right)$ is logically equivalent to
$ \sim p$
$p$
$q$
$ \sim q$
Which of the following is not a statement
Consider the following statements:
$P$ : I have fever
$Q:$ I will not take medicine
$R$ : I will take rest
The statement "If I have fever, then I will take medicine and I will take rest" is equivalent to:
$\sim (p \vee q) \vee (\sim p \wedge q)$ is logically equivalent to
The maximum number of compound propositions, out of $p \vee r \vee s , p \vee P \vee \sim s , p \vee \sim q \vee s$,
$\sim p \vee \sim r \vee s , \sim p \vee \sim r \vee \sim s , \sim p \vee q \vee \sim s$, $q \vee r \vee \sim s , q \vee \sim r \vee \sim s , \sim p \vee \sim q \vee \sim s$
that can be made simultaneously true by an assignment of the truth values to $p , q , r$ and $s$, is equal to
$\left( {p \wedge \sim q \wedge \sim r} \right) \vee \left( { \sim p \wedge q \wedge \sim r} \right) \vee \left( { \sim p \wedge \sim q \wedge r} \right)$ is equivalent to-