A radiation of energy $'E'$ falls normally on a perfectly reflecting surface. The momentum transferred to the surface is $( C =$ Velocity of light $)$
A radiation of energy $'E'$ falls normally on a perfectly reflecting surface. The momentum transferred to the surface is $( C =$ Velocity of light $)$
- [AIPMT 2015]
- [AIEEE 2004]
- A
$\frac{E}{{C\;}}$
- B
$\;\frac{{2E}}{C}$
- C
$\;\frac{{2E}}{{{C^2}}}$
- D
$\;\frac{E}{{{C^2}}}$
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- [JEE MAIN 2022]
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