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11.Dual Nature of Radiation and matter
medium
A $10\, kW$ transmitter emits radio waves of wavelength $500\, m$. The number of photons emitted per second by the transmitter is of the order of
A
${10^{37}}$
B
${10^{31}}$
C
${10^{25}}$
D
${10^{43}}$
(AIEEE-2012)
Solution
Power $=\frac{n h c}{\lambda}$
(where, $n=$ no. of photons per second)
$ \Rightarrow n = \frac{{10 \times {{10}^3} \times 500}}{{6.6 \times {{10}^{ – 34}} \times 3 \times {{10}^8}}} \simeq {10^{31}}$
Standard 12
Physics