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11.Dual Nature of Radiation and matter
medium
A 1$\mu$ $A$ beam of protons with a cross-sectional area of $0.5$ sq. mm is moving with a velocity of $3 \times {10^4}m{s^{ - 1}}$. Then charge density of beam is
A
$6.6 \times {10^{ - 4}}C/{m^3}$
B
$6.6 \times {10^{ - 5}}C/{m^3}$
C
$6.6 \times {10^{ - 6}}C/{m^3}$
D
None of these
Solution
(b) For one second, distance = Velocity =$3 \times {10^4}m/\sec $ and
$Q = i \times 1 = {10^{ – 6}}C$.
Charge density $ = \frac{{{\rm{Charge}}}}{{{\rm{Volume}}}}$
$ = \frac{{{{10}^{ – 6}}}}{{3 \times {{10}^4} \times 0.5 \times {{10}^{ – 6}}}} = 6.6 \times {10^{ – 5}}C/{m^3}$.
Standard 12
Physics
