A 140, g ball, in horizontal flight with a speed v₁ of 39.0, m/s , is struck by a bat. After leavi

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4-1.Newton's Laws of Motion

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A $140\, g$ ball, in horizontal flight with a speed $v_1$ of $39.0\, m/s$, is struck by a bat. After leaving the bat, the ball travel in the opposite direction with speed $v_2 = 39.0\, m/s$. If the impact time $\Delta t$ for the ball-bat collision is $1.20\, ms$, what average net force acts on the ball ......... $N$

A

$1308$

B

$1090$

C

$9100$

D

$980$

Solution

$\mathrm{F}=\frac{\Delta \mathrm{P}}{\mathrm{t}}$

$F=\frac{m\left(v_{2}-v_{1}\right)}{t}=\frac{140}{1000} \frac{[39-(-39)]}{1.2 \times 10^{-3}}$

$=\frac{2 \times 140 \times 39}{1000 \times 1.2 \times 10^{-3}}=9100 \mathrm{N}$

Standard 11

Physics

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