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4-2.Friction
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A $500 \,kg$ horse pulls a cart of mass $1500\, kg $ along a level road with an acceleration of $1\,m{s^{ - 2}}$. If the coefficient of sliding friction is $0.2$, then the force exerted by the horse in forward direction is ......... $N$
A$3000 $
B$4000$
C$5000$
D$6000$
Solution
(d) Net force in forward direction = Accelerating force + Friction
$ = ma + \mu \;mg = m(a + \mu \;g) = (1500 + 500)(1 + 0.2 \times 10)$
$ = 2000 \times 3 = 6000\;N$
$ = ma + \mu \;mg = m(a + \mu \;g) = (1500 + 500)(1 + 0.2 \times 10)$
$ = 2000 \times 3 = 6000\;N$
Standard 11
Physics
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