A $12 \;pF$ capacitor is connected to a $50 \;V$ battery. How much electrostatic energy is stored in the capacitor?
A $12 \;pF$ capacitor is connected to a $50 \;V$ battery. How much electrostatic energy is stored in the capacitor?
Capacitor of the capacitance, $C =12 \,pF =12 \times 10^{-12}\, F$
Potential difference, $V =50 \,V$
Electrostatic energy stored in the capacitor is given by the relation,
$E=\frac{1}{2} C \,V^{2}=\frac{1}{2} \times 12 \times 10^{-12} \times(50)^{2} \,J$ $=1.5 \times 10^{-8}\, J$
Therefore, the electrostatic energy stored in the capacitor is $1.5 \times 10^{-8} \;J$
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