N identical condensers are joined in parallel and are charged to potential V . Now they are separate

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2. Electric Potential and Capacitance

medium

$n$ identical condensers are joined in parallel and are charged to potential $V$. Now they are separated and joined in series. Then the total energy and potential difference of the combination will be

Energy and potential difference remain same

Energy remains same and potential difference is $nV$

Energy increases $n$ times and potential difference is $nV$

Energy increases $n$ times and potential difference remains same

Solution

(b) According to energy conservation, energy remains the same
$==>$ ${U_{parallel}} = {U_{series}}$ $==>$ $\frac{1}{2}(nC){V^2} = \frac{1}{2}\left( {\frac{C}{n}} \right)\,V{'^2}$ $==> V' = nV$
($V'$ $=$ potential difference across series combination)

Standard 12

Physics

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hard

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medium

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easy

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