A 10 g bullet moving at 200 ,m / s stops after penetrating 5 ,cm of wooden plank. average force exer

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4-1.Newton's Laws of Motion

easy

A $10 g$ bullet moving at $200 \,m / s$ stops after penetrating $5 \,cm$ of wooden plank. The average force exerted on the bullet will be .......... $N$

A

$2000$

B

$-2000$

C

$4000$

D

$-4000$

Solution

(d)

$m=10 \,g , u=200 \,m / s , s=5 \,cm$

final velocity $v=0$

Using $v^2=u^2+2 a s$

$a=\frac{u^2}{2 s}$

and for force $F=-m a$ (retarding force)

Standard 11

Physics

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