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4-1.Newton's Laws of Motion
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A body of mass $ 2 \,kg$ is moving with a velocity $8\, m/s$ on a smooth surface. If it is to be brought to rest in $4 \,seconds$, then the force to be applied is ......... $N$
A
$8$
B
$4$
C
$2 $
D
$1 $
Solution
(b)$F = ma = \frac{{m(u – v)}}{t} = \frac{{2 \times (8 – 0)}}{4} = 4N$
Standard 11
Physics
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