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2. Electric Potential and Capacitance
easy
A $2\,\mu F$ capacitor is charged to $100$ $volt$ and then its plates are connected by a conducting wire. The heat produced is........$J$
A
$1$
B
$0.1$
C
$0.01$
D
$0.001$
Solution
(c) Heat produced = Energy of charged capacitor $ = \frac{1}{2}C{V^2}$
$ = \frac{1}{2} \times (2 \times {10^{ – 6}}) \times {(100)^2} = 0.01\,J$
Standard 12
Physics
