Gujarati
4.Moving Charges and Magnetism
medium

$2\, MeV$ ऊर्जायुक्त एक प्रोटॉन, एकसमान चुम्बकीय क्षेत्र $2.5\,tesla$ के लम्बवत् गति करता है, तो प्रोटॉन पर आरोपित बल होगा

A

$2.5 \times {10^{ - 10}}\,N$

B

$7.6 \times {10^{ - 11}}\,N$

C

$2.5 \times {10^{ - 11}}\,N$

D

$7.6 \times {10^{ - 12}}\,N$

Solution

$F = qvB = 1.6 \times {10^{ – 19}} \times \left[ {\sqrt {\frac{{2E}}{m}} } \right]\;2.5$

$ = 4 \times {10^{ – 19}}\sqrt {\frac{{2 \times 2 \times 1.6 \times {{10}^{ – 19}} \times {{10}^6}}}{{1.66 \times {{10}^{ – 27}}}}} $$ = 7.6 \times {10^{ – 12}}N$

Standard 12
Physics

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