Gujarati
14.Probability
easy

A bag contains $19$ tickets numbered from $1$ to $19$. A ticket is drawn and then another ticket is drawn without replacement. The probability that both the tickets will show even number, is

A

$\frac{9}{{19}}$

B

$\frac{8}{{18}}$

C

$\frac{9}{{18}}$

D

$\frac{4}{{19}}$

Solution

(d) The probability of getting an even number in first draw $ = \frac{9}{{19}}$.

The probability of getting an even number in second draw $ = \frac{8}{{18}}$.

Both are independent event and so required probability

$ = \frac{9}{{19}} \times \frac{8}{{18}} = \frac{4}{{19}}.$

Standard 11
Mathematics

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