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14.Probability
easy
A bag contains $19$ tickets numbered from $1$ to $19$. A ticket is drawn and then another ticket is drawn without replacement. The probability that both the tickets will show even number, is
A
$\frac{9}{{19}}$
B
$\frac{8}{{18}}$
C
$\frac{9}{{18}}$
D
$\frac{4}{{19}}$
Solution
(d) The probability of getting an even number in first draw $ = \frac{9}{{19}}$.
The probability of getting an even number in second draw $ = \frac{8}{{18}}$.
Both are independent event and so required probability
$ = \frac{9}{{19}} \times \frac{8}{{18}} = \frac{4}{{19}}.$
Standard 11
Mathematics
