Gujarati
5.Work, Energy, Power and Collision
medium

A ball is moving to and fro about the lowest point $A$ of a smooth hemispherical bowl. If it is able to rise up to a height of $20 \,cm$ on either side of $A$, its speed at $A$ must be  .......... $m/s$ (Take = $10 m/s^2$, mass of the body $5 \,g$)

A$0.2 $
B$2$
C$4$
D$4.5$

Solution

(b)$v = \sqrt {2gh} = \sqrt {2 \times 10 \times 0.2} = 2\,m/s$
Standard 11
Physics

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