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5.Work, Energy, Power and Collision
easy
A body of mass $1\, kg$ is moving in a vertical circular path of radius $1\,m$. The difference between the kinetic energies at its highest and lowest position is ......... $J$
A
$20$
B
$10$
C
$4\sqrt 5 $
D
$10\left( {\sqrt 5 - 1} \right)$
Solution
(a)Difference in kinetic energy = $2mg\,r = 2 \times 1 \times 10 \times 1 = 20J$
Standard 11
Physics