Gujarati
5.Work, Energy, Power and Collision
easy

A body of mass $1\, kg$ is moving in a vertical circular path of radius $1\,m$. The difference between the kinetic energies at its highest and lowest position is ......... $J$

A

$20$

B

$10$

C

$4\sqrt 5 $

D

$10\left( {\sqrt 5 - 1} \right)$

Solution

(a)Difference in kinetic energy = $2mg\,r = 2 \times 1 \times 10 \times 1 = 20J$

Standard 11
Physics

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