A ball is projected upwards from the top of a tower with a velocity of $50\, ms^{-1}$  making an angle of $30^o$ with the horizontal. The height of the tower is $70\, m$. After how  many seconds from the instant of throwing will the ball reach the ground ?.......$s$

The velocity of projectile at the intial point $A$ is $\left( {2\hat i + 3\hat j} \right)$ $m/s $ . It's velocity (in $m/s$) at point $B$ is

A ball is projected with velocity ${V_o}$ at an angle of elevation $30^°$. Mark the correct statement

A projectile is thrown upward with a velocity $v_0$ at an angle $\alpha$ to the horizontal. The change in velocity of the projectile when it strikes the same horizontal plane is

Three balls of same masses are projected with equal speeds at angle $15^{\circ}, 45^{\circ}, 75^{\circ}$, and their ranges are respectively $R_1, R_2$ and $R_3$, then

A cricket ball is thrown at a speed of $28\; m /s$ in a direction $30^o$ above the horizontal. Calculate

$(a)$ the maximum height,

$(b)$ the time taken by the ball to return to the same level, and

$(c)$ the distance from the thrower to the point where the ball returns to the same level