A ball is thrown from a point with a speed {vₒ} at an angle of projection θ . From same point and

English

Gujarati

Hindi

3-2.Motion in Plane

medium

A ball is thrown from a point with a speed ${v_o}$ at an angle of projection $\theta $. From the same point and at the same instant a person starts running with a constant speed ${v_o}/2$ to catch the ball. Will the person be able to catch the ball? If yes, what should be the angle of projection

A

Yes, ${60^o}$

B

Yes, ${30^o}$

C

No

D

Yes, ${45^o}$

(AIEEE-2004)

Solution

(a) Person will catch the ball if its velocity will be equal to horizontal component of velocity of the ball.

$\frac{{{v_0}}}{2} = {v_0}\cos \theta $

$⇒$ $\cos \theta = \frac{1}{2}$

$⇒$ $\theta = 60^\circ $

Standard 11

Physics

Share

Similar Questions

A fighter plane is flying horizontally at a height of $250\ m$ from ground with constant velocity of $500\ m/s$. It passes exactly over a cannon which can fire a shell at any time in any direction with a speed of $100\ m/s$. Find the duration of time for which the plane is in danger of being hit by a cannon shell

normal

An arrow is shot into air. Its range is $200\,m$ and its time of flight is $5\,s$. If $g=10\,m / s ^2$, then horizontal component of velocity and the maximum height will be respectively

medium

In the graph shown in figure, which quantity associated with projectile motion is plotted along $y$-axis?

easy

A football player throws a ball with a velocity of $50$ metre/sec at an angle $30 $ degrees from the horizontal. The ball remains in the air for …… $\sec$ $(g = 10\,m/{s^2})$

easy

At what angle the particle should be projected to cover maximum range ?

easy