A ball of mass 0.2, kg moves with a velocity of 20 ,m/sec and it stops in 0.1 ,sec ; then force on b

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4-1.Newton's Laws of Motion

easy

A ball of mass $0.2\, kg$ moves with a velocity of $20 \,m/sec$ and it stops in $0.1 \,sec$; then the force on the ball is ........... $N$

A

$40$

B

$20$

C

$4$

D

$2$

Solution

(a)$F = ma$ $ = \frac{{m\Delta v}}{{\Delta t}} = \frac{{0.2 \times 20}}{{0.1}} = 40\;N$

Standard 11

Physics

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