A 140,g ball, in horizontal flight with a speed of 39.0,m/s , is struck by a bat. After leaving bat,

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4-1.Newton's Laws of Motion

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A $140\,g$ ball, in horizontal flight with a speed of $39.0\,m/s$, is struck by a bat. After leaving the bat, the ball travels in the opposite direction with speed $39.0\,m/s$. If the impact time $\Delta t$ for the ball-bat collision is $1.20\,ms$, ............ $N$ average force acts on the ball .

A

$1308$

B

$1090$

C

$9100$

D

$980$

Solution

$\mathrm{F}=\frac{\mathrm{m} \Delta \mathrm{v}}{\mathrm{t}}=\frac{140 \times 10^{-3}[39-(-39)]}{1.2 \times 10^{-3}}=9100 \mathrm{N}$

Standard 11

Physics

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