2.Motion in Straight Line
medium

A ball of mass $0.5 \; kg$ is dropped from the height of $10 \; m$. The height, at which the magnitude of velocity becomes equal to the magnitude of acceleration due to gravity, is $\dots \; m$. (Use $g =10 \; m / s ^{2}$).

A

$1$

B

$3$

C

$5$

D

$7$

(JEE MAIN-2022)

Solution

$v^{2}=u^{2}+2 a s$

$100=0+2(10) \,s$

$s=5\, m$

Height from ground $=10-5=5 \,m$

Standard 11
Physics

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