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2.Motion in Straight Line
medium
A ball of mass $0.5 \; kg$ is dropped from the height of $10 \; m$. The height, at which the magnitude of velocity becomes equal to the magnitude of acceleration due to gravity, is $\dots \; m$. (Use $g =10 \; m / s ^{2}$).
A
$1$
B
$3$
C
$5$
D
$7$
(JEE MAIN-2022)
Solution
$v^{2}=u^{2}+2 a s$
$100=0+2(10) \,s$
$s=5\, m$
Height from ground $=10-5=5 \,m$
Standard 11
Physics