A ball of mass m is thrown vertically upwards. Another ball of mass 2 m is thrown at an angle θ wit

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3-2.Motion in Plane

easy

A ball of mass $m$ is thrown vertically upwards. Another ball of mass $2\ m$ is thrown at an angle $\theta $ with the vertical. Both of them stay in air for same period of time. The heights attained by the two balls are in the ratio of

A$2:1$

B$1:\cos \theta $

C$1:1$

D$\cos \theta :1$

Solution

(c) The vertical components of velocity of both the balls will be same if they stay in air for the same period of time. Hence vertical height attained will be same.

Standard 11

Physics

A projectile is fired at an angle of $45^o $ with the horizontal . Elevation angle of the projectile at its highest point as seen from the point of projection, is

hard

(AIPMT-2011)

For a given angle of the projectile if the initial velocity is doubled the range of the projectile becomes

medium

(AIIMS-2011)

If the initial velocity in horizontal direction of a projectile is unit vector $\hat{i}$ and the equation of trajectory is $y =5 x (1- x )$. The $y$ component vector of the initial velocity is.
(Take $g=10\,m / s ^{2}$ )

medium

(JEE MAIN-2022)

A projectile crosses two walls of equal height $H$ symmetrically as shown The time of flight $T$ is given by …….. $\sec$

medium

The horizontal range and maximum height attained by a projectile are $R$ and $H$, respectively. If a constant horizontal acceleration $a=g / 4$ is imparted to the projectile due to wind, then its horizontal range and maximum height will be

medium

A ball of mass $m$ is thrown vertically upwards. Another ball of mass $2\ m$ is thrown at an angle $\theta $ with the vertical. Both of them stay in air for same period of time. The heights attained by the two balls are in the ratio of

Solution

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If the initial velocity in horizontal direction of a projectile is unit vector $\hat{i}$ and the equation of trajectory is $y =5 x (1- x )$. The $y$ component vector of the initial velocity is.
(Take $g=10\,m / s ^{2}$ )