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3-2.Motion in Plane
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The horizontal range and maximum height attained by a projectile are $R$ and $H$, respectively. If a constant horizontal acceleration $a=g / 4$ is imparted to the projectile due to wind, then its horizontal range and maximum height will be
A
$(R+H), \frac{H}{2}$
B
$\left(R+\frac{H}{2}\right), 2 H$
C
$( R +2 H ), H$
D
$(R+H), H$
Solution
(d)
$H=H$ (as vertical component of acceleration has not changed)
$R^{\prime} =u_x T+\frac{1}{2} a_x T^2$
$=R+\frac{1}{2} \times \frac{g}{4} \times \frac{4 u^2 \sin ^2 \theta}{g^2}$
$=R \frac{u^2 \sin ^2 \theta}{2 g}=(R+H)$
Standard 11
Physics
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