A ball of mass $m_1$ and another ball of mass $m_2$ are dropped from equal height. If time taken by the balls are $t_1$ and $t_2$ respectively, then

  • A

    ${t_1} = \frac{{{t_2}}}{2}$

  • B

    $t_1 = t_2$

  • C

    $t_1 = 4t_2$

  • D

    ${t_1} = \frac{{{t_2}}}{4}$

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