5.Magnetism and Matter
medium

A bar magnet of magnetic moment $3.0\, A-m^2$ is placed in a uniform magnetic induction field of $2 \times 10^{-5}\, T$. If each pole of the magnet experiences a force of $6 \times 10^{-4} \,N$, the length of the magnet is.....$m$

A

$0.5$

B

$0.3$

C

$0.2$

D

$0.1$

Solution

(d)$F = mB \Rightarrow F = \frac{M}{L} \times B$
$ \Rightarrow 6 \times {10^{ – 4}} = \frac{3}{L} \times 2 \times {10^{ – 5}} \Rightarrow L = 0.1\;m.$

Standard 12
Physics

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