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5.Magnetism and Matter
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A bar magnet of magnetic moment $3.0\, A-m^2$ is placed in a uniform magnetic induction field of $2 \times 10^{-5}\, T$. If each pole of the magnet experiences a force of $6 \times 10^{-4} \,N$, the length of the magnet is.....$m$
A
$0.5$
B
$0.3$
C
$0.2$
D
$0.1$
Solution
(d)$F = mB \Rightarrow F = \frac{M}{L} \times B$
$ \Rightarrow 6 \times {10^{ – 4}} = \frac{3}{L} \times 2 \times {10^{ – 5}} \Rightarrow L = 0.1\;m.$
Standard 12
Physics
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