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14.Probability
easy
A basket contains $5$ apples and $7$ oranges and another basket contains $4$ apples and $8$ oranges. One fruit is picked out from each basket. Find the probability that the fruits are both apples or both oranges
A
$\frac{{24}}{{144}}$
B
$\frac{{56}}{{144}}$
C
$\frac{{68}}{{144}}$
D
$\frac{{76}}{{144}}$
Solution
(d) Required probability $ = \frac{{^5{C_1}{\,^4}{C_1}}}{{^{12}{C_1}^{12}{C_1}}} + \frac{{^7{C_1}{\,^8}{C_1}}}{{^{12}{C_1}{\,^{12}}{C_1}}}$
$ = \frac{{20 + 56}}{{144}} = \frac{{76}}{{144}}$.
Standard 11
Mathematics
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