Gujarati
Hindi
4-1.Newton's Laws of Motion
normal

A block can slide on a smooth inclined plane of inclination $\theta $ kept on the floor of a lift. When the lift is descending with an acceleration $'a'$ . Then the acceleration of the block relative to the incline is

A

$(g - a)\, sin\,\theta $

B

$(g\, -\, a)$

C

$g\, sin\,\theta $

D

$(g\, +\, a) sin\,\theta $

Solution

Let the acceleration of the block kept on an incline is $b$ and its mass is $m$. Since the lift is retarding downwards with a magnitude a, a pseudo force will be applied on the block in downward direction as shown in the fod. $(m a+m g) \sin \theta=m b$

$b=(a+g) \sin \theta$

Standard 11
Physics

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