Gujarati
Hindi
4-1.Newton's Laws of Motion
easy

A block is dragged on a smooth plane with the help of a rope which moves with a velocity $v$ as shown in figure. The horizontal velocity of the block is

A

$v$

B

$\frac{v}{{\sin \,\theta }}$

C

$v\, sin\,\theta$

D

$\frac{v}{{\cos \,\theta }}$

Solution

$x^{2}+h^{2}=y^{2}$

$\Rightarrow 2 \mathrm{x} \frac{\mathrm{dx}}{\mathrm{dt}}+0=2 \mathrm{y} \frac{\mathrm{dy}}{\mathrm{dt}}$

$\Rightarrow \frac{\mathrm{dx}}{\mathrm{dt}}=\frac{\mathrm{y}}{\mathrm{x}} \cdot \mathrm{v}=\frac{\mathrm{v}}{\sin \theta}$

Standard 11
Physics

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