A block of ice of mass 120,g at temperature 0^{circ} C is put in 300,gm of water at 25^{circ} C . xg

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10-1.Thermometry, Thermal Expansion and Calorimetry

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A block of ice of mass $120\,g$ at temperature $0^{\circ} C$ is put in $300\,gm$ of water at $25^{\circ} C$. The $xg$ of ice melts as the temperature of the water reaches $0^{\circ} C$. The value of $x$ is

[Use: Specific heat capacity of water $=4200$

$J\,kg ^{-1} K ^{-1}$, Latent heat of ice $\left.=3.5 \times 10^{5} J\,kg ^{-1}\right]$

A

$90$

B

$89$

C

$95$

D

$100$

(JEE MAIN-2022)

Solution

Energy released by water

$=0.3 \times 2.5 \times 4200=31500\,J$

let $m \ kg$ ice melts

$m \times 3.5 \times 10^{5}=31.500$

$m =\frac{31500 \times 10^{-5}}{3.5}=9000 \times 10^{-5}$

$m =0.09\,kg =90\,gm$

$x =90$

Standard 11

Physics

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