A block of mass $M$ is suspended from a wire of length $L$, area of cross-section $A$ and Young's modulus $Y$. The elastic potential energy stored in the wire is
$\frac{1}{2}\frac{{{M^2}{g^2}L}}{{AY}}$
$\frac{1}{2}\frac{{Mg}}{{AYL}}$
$\frac{1}{2}\frac{{{M^2}{g^2}A}}{{YL}}$
$\frac{1}{2}\frac{{MgY}}{{AL}}$
Why do spring balances show wrong readings of weight after they have been used for a long time ?
An aluminium rod with Young's modulus $Y =7.0$ $\times 10^{10} N / m ^2$ undergoes elastic strain of $0.04 \%$. The energy per unit volume stored in the rod in SI unit is:
The length of a rod is $20\, cm$ and area of cross-section $2\,c{m^2}$. The Young's modulus of the material of wire is $1.4 \times {10^{11}}\,N/{m^2}$. If the rod is compressed by $5\, kg-wt$ along its length, then increase in the energy of the rod in joules will be
Calculate the work done, if a wire is loaded by $'Mg'$ weight and the increase in length is $'l'$
A metal wire having Poisson's ratio $1 / 4$ and Young's modulus $8 \times 10^{10} \,N / m ^2$ is stretched by a force, which produces a lateral strain of $0.02 \%$ in it. The elastic potential energy stored per unit volume in wire is [in $\left.J / m ^3\right]$