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4-1.Newton's Laws of Motion
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A block of mass $8\, kg$ is at rest on a rough inclined plane as shown in figure. The magnitude of net force exerted by the surface on the block will be ......... $N$
A$0$
B$48$
C$64$
D$80$
Solution
Net force applied by block on the inclined plane is equal to the weight of the body.
$\mathrm{N}=\mathrm{mg} \cos \theta$ and $\mathrm{f}_{\mathrm{s}}=\mathrm{mg} \sin \theta$
$\mathrm{F}=\sqrt{\mathrm{f}_{\mathrm{s}}^{2}+\mathrm{N}^{2}}=\mathrm{mg}$
$\mathrm{N}=\mathrm{mg} \cos \theta$ and $\mathrm{f}_{\mathrm{s}}=\mathrm{mg} \sin \theta$
$\mathrm{F}=\sqrt{\mathrm{f}_{\mathrm{s}}^{2}+\mathrm{N}^{2}}=\mathrm{mg}$
Standard 11
Physics
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