Pulleys in diagram are all smooth and light. acceleration of A is a upwards and acceleration of C is

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4-1.Newton's Laws of Motion

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The pulleys in the diagram are all smooth and light. The acceleration of $A$ is $a$ upwards and the acceleration of $C$ is $f$ downwards. The acceleration of $B$ is

A

$\frac{1}{2}(f-a)$ up

B

$\frac{1}{2}(a+f)$ down

C

$\frac{1}{2}(a+f)$ up

D

$\frac{1}{2}(a-f)$ up

Solution

From constrained

$-a-a_B-a_B+f=0$

$a_B=\left(\frac{f}{2}-\frac{a}{2}\right)=\frac{1}{2}(f-a) \uparrow$

Standard 11

Physics

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