Gujarati
Hindi
4-1.Newton's Laws of Motion
normal

A block of mass $m$ lying on a rough horizontal plane is acted upon by a horizontal force $P$ and another force $Q$ inclined an at an angle $\theta$ to the vertical. The minimum value of coefficient of friction between the block and the surface for which the block will remain in equilibrium is :

A

$\frac{P \cos \theta+Q}{m g-Q \sin \theta}$

B

$\frac{P+Q \sin \theta}{m g+Q \cos \theta}$

C

$\frac{P+Q \cos \theta}{m g+Q \sin \theta}$

D

$\frac{P \sin \theta-Q}{m g-Q \cos \theta}$

Solution

$f_r=\mu N=\mu(m g+Q \cos \theta)$

$f_r=P+Q \sin \theta$

$\mu=\frac{(P+Q \sin \theta)}{(m g+Q \cos \theta)}$

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.