A block of mass M is at rest on a plane surface inclined at an angle θ to horizontal. magnitude of

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4-1.Newton's Laws of Motion

easy

A block of mass $M$ is at rest on a plane surface inclined at an angle $\theta$ to the horizontal. The magnitude of force exerted by the plane on the block is

A$M g \cos \theta$

B$M g \tan \theta$

C$M g \sin \theta$

D$M g$

(KVPY-2009)

Solution

(a)
Weight of mass $M$ can be resolved into components parallel and perpendicular to inclined plane as shown below.
Force of block on incline is $M g \cos \theta$, so force exerted by block on mass $M$ is
$M g \cos \theta$ directed perpendicularly up the plane.

Standard 11

Physics

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A block of mass $M$ is at rest on a plane surface inclined at an angle $\theta$ to the horizontal. The magnitude of force exerted by the plane on the block is

Solution

Similar Questions

A body of mass $1\, kg$ lies on smooth inclined plane. The body is given force $F = 10N$ horizontally as shown. The magnitude of net normal reaction on the body is

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