9-1.Fluid Mechanics
easy

A block of steel of size $ 5 cm × 5 cm × 5 cm $ is weighed in water. If the relative density of steel is $7,$  its apparent weight is

A

$6 × 5 × 5 × 5 gf$ 

B

$4 × 4 × 4 × 7 gf$

C

$5 × 5 × 5 × 7 gf$

D

$4 × 4 × 4 × 6 gf$ 

Solution

(a) Apparent weight = $V(\rho – \sigma )g$
= $5 \times 5 \times 5(7 – 1)g$= $6 \times 5 \times 5 \times 5\;gf$

Standard 11
Physics

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