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9-1.Fluid Mechanics
easy
A block of steel of size $ 5 cm × 5 cm × 5 cm $ is weighed in water. If the relative density of steel is $7,$ its apparent weight is
A
$6 × 5 × 5 × 5 gf$
B
$4 × 4 × 4 × 7 gf$
C
$5 × 5 × 5 × 7 gf$
D
$4 × 4 × 4 × 6 gf$
Solution
(a) Apparent weight = $V(\rho – \sigma )g$
= $5 \times 5 \times 5(7 – 1)g$= $6 \times 5 \times 5 \times 5\;gf$
Standard 11
Physics