A block of wood floats in water with frac{4}{ | vedclass

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Question

(b)

$\frac{4}{5} v_b 	imes ho_w 	imes g=v_b 	imes ho_b 	imes g$   $\left\{\begin{array}{l}	ext { Where, } \ v_b=	ext { volume

Vedclass · Accepted Answer

$800$

Vedclass · Answer

(b)

$\frac{4}{5} v_b 	imes ho_w 	imes g=v_b 	imes ho_b 	imes g$   $\left\{\begin{array}{l}	ext { Where, } \ v_b=	ext { volume of block } \ ho_w=	ext { density of water }=1000\,kg / m ^3 \ ho_b=	ext { density of block }\end{array}ight.$

$\Rightarrow \frac{ho_w}{ho_b}=\frac{5}{4}$

$ho_b=\frac{4}{5} 	imes 1000=800 \,kg / m ^3$

And when block is put in liquid of density $ho_f$ it just floats

$	ext { So, } v_b 	imes ho_b 	imes g=v_b 	imes ho_l 	imes g$

$\Rightarrow ho_b=ho_l$

$	ext { So, } ho_l=800 \,kg / m ^3$

A block of wood floats in water with $\frac{4}{5}$ th of its volume submerged, but it just floats in another liquid. The density of liquid is (in $kg / m ^3$ )

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