- Home
- Standard 11
- Physics
2.Motion in Straight Line
medium
A body falling freely under gravity passes two points $30\,m$ apart in $1\,s$ . From what point above the upper point it began to fall?......... $m$ (Take $g = 10\,m\,s^{-2}$ )
A
$31.25$
B
$16$
C
$8.6$
D
$4$
Solution
Suppose the body passes the upper point
at $t$ second and lower point at $(t+1)$ s, then
$\mathrm{S}_{2}-\mathrm{S}_{1}=\frac{1}{2} \mathrm{g}(\mathrm{t}+1)^{2}-\frac{1}{2} \mathrm{gt}^{2}=\frac{1}{2} \mathrm{g}(2 \mathrm{t}+1)$
or $30 \mathrm{m}=\frac{1}{2} \times 10(2 \mathrm{t}+1)$
$\therefore \mathrm{t}=2.5 \mathrm{s}$
$S_{1}=\frac{1}{2} g t^{2}=\frac{1}{2} \times 10 \times(2.5)^{2}=31.25 \mathrm{m}$
Standard 11
Physics
