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2.Motion in Straight Line
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A body is dropped from a height $H$. The time taken to cover second half of the journey is ............
A
$2 \sqrt{\frac{2 H}{g}}$
B
$\sqrt{\frac{H}{g}}$
C
$\sqrt{\frac{H}{g}}(\sqrt{2}-1)$
D
$\sqrt{\frac{2 H}{g}} \times \frac{1}{(\sqrt{2}-1)}$
Solution

(c)
The total time of journey
$-s=u t-\frac{1}{2} g t^2$
$\Rightarrow H=\frac{1}{2} g T^2 \quad \ldots(i)$
$\frac{-H}{2}=u t-\frac{1}{2} g t^2 \Rightarrow T=\sqrt{\frac{2 H}{g}}$
$\Rightarrow \frac{H}{2}=\frac{1}{2} g t^2$
$\Rightarrow \frac{1}{2} g T^2=g t^2 \quad(\because u t=0)$
$\Rightarrow t=\frac{T}{\sqrt{2}}$
$\Rightarrow$ Second half time $=T-t=T-\frac{T}{\sqrt{2}}=T\left(1-\frac{1}{\sqrt{2}}\right)=\sqrt{\frac{2 H}{g}}\left(1-\frac{1}{\sqrt{2}}\right)=\sqrt{\frac{H}{g}}(\sqrt{2}-1)$
Standard 11
Physics
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