From a building two balls $A$ and $B$ are thrown such that $A$ is thrown upwards and $B$ downwards with the same speed (both vertically). If $v_{A}$ and $v_{B}$ are their respective velocities on reaching the ground then,

A ball is released from the top of a tower of height $h$ meters. It takes $T$ seconds to reach the ground. What is the position of the ball in $\frac {T}{3}$ seconds

A body thrown vertically up with initial velocity $52 \,m / s$ from the ground passes twice a point at $h$ height above at an interval of $10 \,s$. The height $h$ is ………$m$ $\left(g=10 \,m / s ^2\right)$

A body is thrown vertically upwards. Which one of the following graphs correctly represent the velocity vs time?

From a tower of height $H$, a particle is thrown vertically upwards with a speed $ u$. The time taken by the particle, to hit the ground, is $n$ times that taken by it to reach the highest point of its path. The relation between $H, u$ and $n$ is: