A body is moving under the action of two forc | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

For uniform velocity, acceleration is zero. Hence resultant force will be zero.

$	herefore \overrightarrow{\mathrm{F}}_{1}+\overrightarrow{\mathrm

Vedclass · Accepted Answer

$-5\hat i + 9\hat j$

Vedclass · Answer

For uniform velocity, acceleration is zero. Hence resultant force will be zero.

$	herefore \overrightarrow{\mathrm{F}}_{1}+\overrightarrow{\mathrm{F}}_{2}+\overrightarrow{\mathrm{F}}_{3}=0$

$(2 \hat{i}-5 \hat{j})+(3 \hat{i}-4 \hat{j})+\vec{F}_{3}=0$

or $\overrightarrow{\mathrm{F}}_{3}=(-5 \hat{\mathrm{i}}+9 \hat{\mathrm{j}})$

A body is moving under the action of two forces ${\vec F_1} = 2\hat i - 5\hat j\,;\,{\vec F_2} = 3\hat i - 4\hat j$. Its velocity will become uniform under an additional third force ${\vec F_3}$ given by

Similar Questions

The three vectors $\overrightarrow A = 3\hat i - 2\hat j + \hat k,\,\,\overrightarrow B = \hat i - 3\hat j + 5\hat k$ and $\overrightarrow C = 2\hat i + \hat j - 4\hat k$ form

Two forces of magnitude $8 \,N$ and $15 \,N$ respectively act at a point. If the resultant force is $17 \,N$, the angle between the forces has to be .......

The vectors $5i + 8j$ and $2i + 7j$ are added. The magnitude of the sum of these vector is

The magnitudes of vectors $\vec A,\,\vec B$ and $\vec C$ are $3, 4$ and $5$ units respectively. If $\vec A + \vec B = \vec C$, the angle between $\vec A$ and $\vec B$ is

Two forces of magnitude $P$ & $Q$ acting at a point have resultant $R$. The resolved part of $R$ in the direction of $P$ is of magnitude $Q$. Angle between the forces is :