Two forces, {F_1} and {F_2} are acting on a b | vedclass

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Question

(c)Let $F 1=F$

and $\quad F 2=2 F$

Resultant force $=F_{	ext {net }}=2 F$

$F_{net}$ $=\sqrt{F_{1}^{2}+F_{2}^{2}+2 F_{1} F_{2}} \cos 	heta$

Vedclass · Accepted Answer

${\cos ^{ - 1}}( - 1/4)$

Vedclass · Answer

(c)Let $F 1=F$

and $\quad F 2=2 F$

Resultant force $=F_{	ext {net }}=2 F$

$F_{net}$ $=\sqrt{F_{1}^{2}+F_{2}^{2}+2 F_{1} F_{2}} \cos 	heta$

$2 F=\sqrt{F^{2}+2 F^{2}+2 	imes F 	imes(2 F) \cos 	heta}$

$4 F^{2}=5 F^{2}+4 F^{2} \cos 	heta$

$4 \cos 	heta=-1$

$	herefore \cos 	heta=\frac{-1}{4}$

Two forces, ${F_1}$ and ${F_2}$ are acting on a body. One force is double that of the other force and the resultant is equal to the greater force. Then the angle between the two forces is

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