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4-1.Newton's Laws of Motion
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A body is moving with a velocity $v$, breaks up into two equal parts. One of the part retraces back with velocity $v$. Then the velocity of the other part is
A
$v$ in forward direction
B
$3v$ in forward direction
C
$v$ in backward direction
D
$3v$ in backward direction
Solution
(b)Let the initial mass of body $= m$
Initial linear momentum = $mv$ …(i)
When it breaks into equal masses then one of the fragment retrace back with same velocity
Final linear momentum = $\frac{m}{2}( – v) + \frac{m}{2}({v_2})$…(ii)
By the conservation of linear momentum
$⇒$$⇒$ $mv = \frac{{ – mv}}{2} + \frac{{m{v_2}}}{2}$$⇒$ ${v_2} = 3v$
i.e. other fragment moves with velocity $3v $ in forward direction
Standard 11
Physics
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