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4-1.Newton's Laws of Motion
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A $1 \;kg$ stationary bomb is exploded in three parts having mass $1: 1: 3$ respectively. Parts having same mass move in perpendicular direction with velocity $30\; ms ^{-1}$, then the velocity of bigger part will be
A
$\frac{10}{\sqrt{2}}\;m/s$
B
$\frac{15}{\sqrt{2}}\;m/s$
C
$15 \sqrt{2}\;m/s$
D
$10 \sqrt{2} \;m/s$
(AIPMT-2001)
Solution
Apply conservation of linear momentum
$\Rightarrow 3 mV =30 \sqrt{2} m$
$\Rightarrow V =10 \sqrt{2}$
Standard 11
Physics
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