A body is projected at an angle of 30^{circ} with horizontal with momentum p . At its highest point,

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4-1.Newton's Laws of Motion

easy

A body is projected at an angle of $30^{\circ}$ with the horizontal with momentum $p$. At its highest point, the magnitude of the momentum is

A

$\frac{\sqrt{3}}{2}\,p$

B

$\frac{2}{\sqrt{3}}\,p$

C

$p$

D

$\frac{p}{2}$

Solution

(a)

At highest point velocity will remain $v \cos 30^{\circ}$ or $\frac{\sqrt{3}\,v}{2}$. Therefore, momentum will also remain $\frac{\sqrt{3}\,p}{2}$.

Standard 11

Physics

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