A body of 5 ,kg is moving with a velocity of 20 ,m/s . If a force of 100,N is applied on it for 10,s

English

Gujarati

Hindi

4-1.Newton's Laws of Motion

easy

A body of $5 \,kg$ is moving with a velocity of $20 \,m/s$. If a force of $100\,N$ is applied on it for $10\,s$ in the same direction as its velocity, what will now be the velocity of the body.........$m/s$

A

$200 $

B

$220$

C

$240$

D

$260 $

Solution

(b)$v = u + at = u + \left( {\frac{F}{m}} \right)t = 20 + \left( {\frac{{100}}{5}} \right) \times 10 = 220\,\;m/s$

Standard 11

Physics

Share

Similar Questions

A particle of mass $m$ moves with constant speed $v$ on a circular path of radius $r$ as shown in figure. The average force on it during its motion from $A$ to $B$ is

medium

A constant retarding force of $50\; N$ is applied to a body of mass $20\; kg$ moving initially with a speed of $15\; m/s$. How long (in $sec$) does the body take to stop ?

medium

A machine gun fires a bullet of mass $40\, g$ with a velocity $1200\, ms^{-1}$. The man holding it, can exert maximum force of $144\, N$ on the gun. How many bullets can he fire per second at the most ?

easy

A body of mass $0.40 \;kg$ moving initially with a constant speed of $10 \;m s ^{-1}$ to the north is subject to a constant force of $8.0\; N$ directed towards the south for $30\; s$. Take the instant the force is applied to be $t=0,$ the position of the body at that time to be $x=0,$ and predict its position at $t=-5\; s, 25\; s, 100 \;s.$

medium

A body of mass $4 \mathrm{~kg}$ experiences two forces $\overrightarrow{\mathrm{F}}_1=5 \hat{\mathrm{i}}+8 \hat{\mathrm{j}}+7 \hat{\mathrm{k}}$ and $\overrightarrow{\mathrm{F}}_2=3 \hat{\mathrm{i}}-4 \hat{\mathrm{j}}-3 \hat{\mathrm{k}}$. The acceleration acting on the body is :

medium

(JEE MAIN-2024)