A body of mass 1,kg crosses a point O with a velocity 60,ms^{-1}. A force of 10,N directed towards O

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4-1.Newton's Laws of Motion

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A body of mass $1\,kg$ crosses a point $O$ with a velocity $60\,ms^{-1}.$ A force of $10\,N$ directed towards $O$ begins to act on it. It will again cross $O$ in ........ $\sec$

A

$24$

B

$12$

C

$6$

D

will never return to $O$

Solution

$a=\frac{f}{m}=\frac{10}{T}=10 m / s^{2}$

$T=\frac{2 u}{a}=2 \times \frac{60}{10}=12 s$

Standard 11

Physics

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