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5.Work, Energy, Power and Collision
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A body of mass $1\,kg$ is rotating in a vertical circle of radius $1\,m$. What will be the difference in its kinetic energy at the top and bottom of the circle : ............ $\mathrm{J}$ $(g = 10\,m/s^2)$
A
$10$
B
$20$
C
$30$
D
$50$
Solution
$\Delta KE = \frac{1}{2}\,\,m\,[5gr – gr]\, = \,2mgr\, = \,20\,J$
Standard 11
Physics
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