Gujarati
Hindi
5.Work, Energy, Power and Collision
medium

A body of mass $1\,kg$ is rotating in a vertical circle of radius $1\,m$. What will be the difference in its kinetic energy at the top and bottom of the circle : ............ $\mathrm{J}$ $(g = 10\,m/s^2)$

A

$10$

B

$20$

C

$30$

D

$50$

Solution

$\Delta KE = \frac{1}{2}\,\,m\,[5gr – gr]\, = \,2mgr\, = \,20\,J$

Standard 11
Physics

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